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hi ,
i'v got a problem i made a form but when i wanted to make the thank you page the php code im suppose to copy, and place my email there is not visable all i see is,
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>thank you</title>
<meta name="GENERATOR" content="Created by BlueVoda">
<script type="text/javascript">
<!--
function SwapImage()
{
var doc=document, args=arguments;
doc.$imgSwaps = new Array();
for(var i=2; i<args.length; i+=2)
{
var elem=FindObject(args[i]);
if(elem)
{
doc.$imgSwaps[doc.$imgSwaps.length]=elem;
elem.$src=elem.src;
elem.src=args[i+1];
}
}
}
what do you advice me to do?
thank you
faisal
i'v got a problem i made a form but when i wanted to make the thank you page the php code im suppose to copy, and place my email there is not visable all i see is,
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>thank you</title>
<meta name="GENERATOR" content="Created by BlueVoda">
<script type="text/javascript">
<!--
function SwapImage()
{
var doc=document, args=arguments;
doc.$imgSwaps = new Array();
for(var i=2; i<args.length; i+=2)
{
var elem=FindObject(args[i]);
if(elem)
{
doc.$imgSwaps[doc.$imgSwaps.length]=elem;
elem.$src=elem.src;
elem.src=args[i+1];
}
}
}
what do you advice me to do?
thank you
faisal
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